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December 22, 2014

December 22, 2014

Posted by **Meaghan** on Saturday, March 7, 2009 at 11:22pm.

t = time

Equation:

192(t+3) = 960

2)An airplane flew for 4 hours with a 20-km/h tail wind. The return flight against the same wind took 5 hours. Find the speed of the plane in still air.

r = rate in which the plane is moving

Equation:

4(r+20 = 5(r-20)

3) It takes a passenger train 2 hours less time than it takes a reight train to make the trip from Central City to Clear Creek. The passenger train averages 96 km/h while the freight train averages 63 km/h. How far is it from Central City to Clear Creek?

On this one, I don't know.

- Algebra: 8th Grade; Equation Check -
**drwls**, Sunday, March 8, 2009 at 12:45am3) freight train's time = D/63

= D/96 + 2

D/63 - D/96 = 33 D /6048 = 2

D = 12096/33 = 366.55 miles

- Algebra: 8th Grade (#1) -
**drwls**, Sunday, March 8, 2009 at 12:51am1) You had the wrong equation on the first one. It should be

192(t+3) = 960t, where t is the time the jet plane leaves.

2) Your equation is ok here, if r is the speed in still air

- Algebra: 8th Grade; Equation Check -
**Meaghan**, Sunday, March 8, 2009 at 1:18amI don't get number 3

and I am sorry, but I made a typo.

The freight train travels at 64 km/h.

If the passenger train takes 2 hours LESS time than it takes the Freight train to make the trip from Central Park to Clear Creek.

how is the equation:

D/63 = D/96 + 2

make sense.

shouldn't it be d/96 = d/64 - 2 ??

- Algebra: 8th Grade; Equation Check -
**drwls**, Sunday, March 8, 2009 at 3:37amWith 64 instead of 63 you will get an integer answer, 12096/32 = 378. Do the math the same way.

d/96 = d/64 - 2 is basically what I wrote, but rearranged and with your corrected 64 in place of the 63.

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