Posted by A.W. on Friday, March 6, 2009 at 4:53pm.
I just did your earlier problem. Please study that. If you can do one you can do them all.
first if you have .3 x in both, why multiply by 10?
.3 x - .2 y = 4
.3 x + .3 y = 5/19
subtract second from first
0 x - .5 y = 71/19
y = - 142/19
so
.3 x - .2 (-142/19) = 40
3 x = -2(142/19) + 760/19
3 x = 476/19
x = 476/57
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