Friday

March 6, 2015

March 6, 2015

Posted by **A.W.** on Friday, March 6, 2009 at 4:53pm.

- Algebra -
**Damon**, Friday, March 6, 2009 at 4:54pmI just did your earlier problem. Please study that. If you can do one you can do them all.

- Algebra -
**Damon**, Friday, March 6, 2009 at 5:00pmfirst if you have .3 x in both, why multiply by 10?

.3 x - .2 y = 4

.3 x + .3 y = 5/19

subtract second from first

0 x - .5 y = 71/19

y = - 142/19

so

.3 x - .2 (-142/19) = 40

3 x = -2(142/19) + 760/19

3 x = 476/19

x = 476/57

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