Posted by **A.W.** on Friday, March 6, 2009 at 4:53pm.

How do I solve for elimination method on this problem: 0.3x - 0.2y=4 and 0.3x + 0.3y= 5/19. I know that multiply by 10 on both equations and get 3x-2y=40 and 3x+3y=50/19. and then I have to multiply 3x-3y=40 by 3 and 3x+3y= 50/19 by -3 to get 9x-9y=120 and -9x-9y=-150/19. But from there I get lost. Can someone please help me?

- Algebra -
**Damon**, Friday, March 6, 2009 at 4:54pm
I just did your earlier problem. Please study that. If you can do one you can do them all.

- Algebra -
**Damon**, Friday, March 6, 2009 at 5:00pm
first if you have .3 x in both, why multiply by 10?

.3 x - .2 y = 4

.3 x + .3 y = 5/19

subtract second from first

0 x - .5 y = 71/19

y = - 142/19

so

.3 x - .2 (-142/19) = 40

3 x = -2(142/19) + 760/19

3 x = 476/19

x = 476/57

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