Posted by Cassie on Friday, March 6, 2009 at 3:52pm.
(2^16)^x = (16^2)^x
16^2^x = [(2^4)^2]^x
and
a^b^c = a^(bc)
so
2^16 x = 2^8x
16 x log 2 = 8 x log 2
16 x = 8 x ?
not unless x = 0
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