Posted by John on Thursday, March 5, 2009 at 8:09pm.
if sin s = -5 /13
and sin t -3/5
s is in QIII
t is in QIV
find tan (s-t)
i got that tan (s-t)= 56/53
is that right? can someone check my work?
- TRIG - drwls, Thursday, March 5, 2009 at 11:58pm
If sin s = -5/13, and it is in the third quadrant, cos s = -12/13
s = 202.620 degrees
If sin t is -3/5, and t is in the fourth quadrant, cos t = 4/5.
t = 323.130 degrees
tan (s-t) = sin (s-t)/cos(s-t)
= [sin s cos t - sin t cos s]/
[cos s cos t + sin s sin t]
Crunch the numbers. You should get a rational fraction, but your 53 in the denominator looks fishy.
You answer should be 56/33.
Answer this Question
- Trig - Given: cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 < v < ...
- trig - If sin A= 1/4 and sin B= -1/2, with A in QII and B in QIV, find tan(A+B)
- Trig Identities - Proving identities: 1) 1+ 1/tan^2x = 1/sin^2x 2) 2sin^2 x-1 = ...
- precalculus - For each of the following determine whether or not it is an ...
- Trigonometry - Please review and tell me if i did something wrong. Find the ...
- Trig....... - I need to prove that the following is true. Thanks (2tanx /1-tan^x...
- trig 26 - simplify to a constant or trig func. 1. sec Ču-tan Ču/cos Čv+sin Čv ...
- Maths Calculus Derivatives - Find the first derivative for the following ...
- MathsSs triG - Consider sin(x-360)sin(90-x)tan(-x)/cos(90+x) 1.A.SIMPLIFY sin(x-...
- calculus - I need help on finding the local linear approximation of tan 62 ...