Posted by John on Thursday, March 5, 2009 at 8:09pm.
if sin s = -5 /13
and sin t -3/5
s is in QIII
t is in QIV
find tan (s-t)
i got that tan (s-t)= 56/53
is that right? can someone check my work?
TRIG - drwls, Thursday, March 5, 2009 at 11:58pm
If sin s = -5/13, and it is in the third quadrant, cos s = -12/13
s = 202.620 degrees
If sin t is -3/5, and t is in the fourth quadrant, cos t = 4/5.
t = 323.130 degrees
tan (s-t) = sin (s-t)/cos(s-t)
= [sin s cos t - sin t cos s]/
[cos s cos t + sin s sin t]
Crunch the numbers. You should get a rational fraction, but your 53 in the denominator looks fishy.
You answer should be 56/33.
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