a 3digit, and 1digit number have a sum of 147, a different of 133 and a product of 980. find the numbers, and then give their quatient
From the information above:
x - y = 133
x + y = 147
Find the value for x in one formula.
x = y + 133
Substitute that for x in the second formula and solve for y.
(y + 133) + y = 147
2y = 147 - 133 = 14
y = 7
Put the y value into the first formula and solve for x.
x = y + 133 = 7 + 133 = 140
Check by finding their product.
I hope this helps. Thanks for asking.