Posted by **sara** on Wednesday, March 4, 2009 at 10:32pm.

Identical +7.74 C charges are fixed to adjacent corners of a square. What charge (magnitude and algebraic sign) should be fixed to one of the empty corners, so that the total potential at the remaining empty corner is 0 V?

I thought that this is what i should do. But I cant get the correct answer...

the total potential is

V = k[7.74C/r + 7.74C/2 *r + q/r]

0 = k/a[(7.74C+q)2 + 7.74C]

or (7.74C+q)2 = - 7.74C

q = -7.74C[1+1/2]

So that gives me q=-13.23. I am told that that is the wrong answer. Please help!

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