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Identical +7.74 ƒÊC charges are fixed to adjacent corners of a square. What charge (magnitude and algebraic sign) should be fixed to one of the empty corners, so that the total potential at the remaining empty corner is 0 V?

I thought that this is what i should do. But I cant get the correct answer...

the total potential is
V = k[7.74ƒÊC/r + 7.74ƒÊC/ã2 *r + q/r]
0 = k/a[(7.74ƒÊC+q)ã2 + 7.74ƒÊC]
or (7.74ƒÊC+q)ã2 = - 7.74ƒÊC
q = -7.74ƒÊC[1+1/ã2]

So that gives me q=-13.23. I am told that that is the wrong answer. Please help!

  • physics -

    This looks like a question posted earlier, but in less legible form. I believe BobPursley agreed with your answer. I also got the same answer.

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