When 9.8g of aluminum oxide(Al2O3) decomposes, how many frams of aluminum metal are produced?

a). Multiply the atomic mass of Al by 2 = _____?

b). Multiply the atomic mass of O by 3 = _____?
c). Add (a) and (b) to get the formula mass of Al2O3
d). Find the % of Al in Al2O3:
%Al = [(a)/(c)]*(100)
e). Multiply the mass of Al2O3 given in the question by the % of Al. Divide the answer by 100 to get the mass of Al in the sample. It should be less than 9.8 g.

To determine how many grams of aluminum metal are produced when 9.8g of aluminum oxide (Al2O3) decomposes, we first need to determine the molecular weights of aluminum oxide and aluminum.

The molecular weight of aluminum oxide (Al2O3) can be calculated by adding the atomic weights of aluminum (Al) and oxygen (O):
- Aluminum (Al) has an atomic weight of 26.98 g/mol.
- Oxygen (O) has an atomic weight of 16.00 g/mol.

So, the molecular weight of aluminum oxide (Al2O3) is:
2(Al) + 3(O) = 2(26.98) + 3(16.00) = 101.96 g/mol

Given that 9.8g of aluminum oxide (Al2O3) decomposes, we can calculate the number of moles of aluminum oxide using the formula:
moles = mass / molecular weight

Moles of Al2O3= 9.8g / 101.96 g/mol = 0.096 moles of Al2O3

Since the decomposition of aluminum oxide (Al2O3) produces aluminum (Al) in a 1:2 ratio, we can determine the moles of aluminum produced:
moles of Al = 2 x moles of Al2O3 = 2 x 0.096 moles = 0.192 moles of Al

Finally, we can calculate the grams of aluminum produced using the formula:
mass = moles x molecular weight

Mass of Al = 0.192 moles x 26.98 g/mol = 5.184g

Therefore, when 9.8g of aluminum oxide (Al2O3) decomposes, approximately 5.184g of aluminum metal is produced.

To determine how many grams of aluminum metal are produced when 9.8g of aluminum oxide (Al2O3) decomposes, we need to understand the chemical equation for the decomposition reaction.

The balanced equation for the decomposition of aluminum oxide is:
2Al2O3 → 4Al + 3O2

According to the balanced equation, for every 2 moles of Al2O3, we get 4 moles of Al. Now, we need to convert grams of Al2O3 to moles using its molar mass.

The molar mass of Al2O3 is calculated by adding the molar masses of aluminum (Al) and oxygen (O):
Al: 1 mole × atomic weight of Al (26.98 g/mole)
O: 3 moles × atomic weight of O (16.00 g/mole)

Al2O3: (2 × 26.98 g/mole) + (3 × 16.00 g/mole) = 101.96 g/mole

Now, we can calculate the number of moles of Al2O3 in 9.8g using the formula:
moles = mass (g) / molar mass (g/mole)

moles of Al2O3 = 9.8 g / 101.96 g/mole

Next, we can use the mole ratio from the balanced equation to find the number of moles of aluminum (Al) produced. According to the equation, for every 2 moles of Al2O3, we get 4 moles of Al.

moles of Al = (moles of Al2O3) × (4 moles Al / 2 moles Al2O3)

Finally, to find the mass of aluminum (Al) produced, we multiply the number of moles of Al by its molar mass (atomic weight of Al: 26.98 g/mole).

mass of Al = (moles of Al) × (molar mass of Al)

By following these calculations, you can find the number of grams of aluminum metal produced when 9.8g of aluminum oxide decomposes.