Posted by **Sarah** on Wednesday, March 4, 2009 at 5:28pm.

Identical +7.74 μC charges are fixed to adjacent corners of a square. What charge (magnitude and algebraic sign) should be fixed to one of the empty corners, so that the total potential at the remaining empty corner is 0 V?

I thought that this is what i should do. But I cant get the correct answer...

the total potential is

V = k[7.74μC/r + 7.74μC/√2 *r + q/r]

0 = k/a[(7.74μC+q)√2 + 7.74μC]

or (7.74μC+q)√2 = - 7.74μC

q = -7.74μC[1+1/√2]

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