Homework Help: physics

Posted by Sarah on Wednesday, March 4, 2009 at 5:28pm.

Identical +7.74 μC charges are fixed to adjacent corners of a square. What charge (magnitude and algebraic sign) should be fixed to one of the empty corners, so that the total potential at the remaining empty corner is 0 V?

I thought that this is what i should do. But I cant get the correct answer...

the total potential is
V = k[7.74μC/r + 7.74μC/√2 *r + q/r]
0 = k/a[(7.74μC+q)√2 + 7.74μC]
or (7.74μC+q)√2 = - 7.74μC
q = -7.74μC[1+1/√2]

physics - bobpursley, Wednesday, March 4, 2009 at 6:06pm
correct.
physics - sarah, Wednesday, March 4, 2009 at 10:30pm
So that gives me q=-13.23. I am told that that is the wrong answer. Please help!

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