Find the indicated intersection or union.

{q, s, u, v, w, x, y, z}*{q, s, y, z}

I think its E. Any feedback is appreciated!

A) {s, u, w}
B) {v, x}
C) {q, s, u, v, w, x, y, z}
D) {s, u, v, w, x, z}
E) None of the above

so which one is it you want, the intersection or the union ?

Is there both in this equation? I need both I would say, it says either or. Does this help? Thanks!

To find the indicated intersection or union, we need to understand the concepts of intersection and union.

The intersection of two sets, denoted by the symbol ∩, is the set of elements that are common to both sets. In other words, it includes only the elements that are present in both sets.

The union of two sets, denoted by the symbol ∪, is the set that contains all the elements from both sets, without any duplicates.

In this case, we have two sets:
Set 1: {q, s, u, v, w, x, y, z}
Set 2: {q, s, y, z}

To find the intersection, we need to identify the elements that are present in both sets. By comparing the elements of both sets, we can see that the elements "q," "s," "y," and "z" are present in both sets.

To find the union, we need to combine all the elements from both sets and remove any duplicates. By combining the elements of both sets, we get the set {q, s, u, v, w, x, y, z}.

Now, let's compare the options provided:

A) {s, u, w}: This set does not include all the elements from both sets, so it is not the correct answer.
B) {v, x}: This set only includes some of the elements from both sets, so it is not the correct answer.
C) {q, s, u, v, w, x, y, z}: This set includes all the elements from both sets, so it is a valid union. However, the question asks for the intersection or union, so we need to check the other options before confirming.
D) {s, u, v, w, x, z}: This set only includes some of the elements from both sets, so it is not the correct answer.
E) None of the above: This option is the correct answer since none of the other options match the intersection or union of the two sets.

Therefore, the answer is E) None of the above.