What is a balanced equation for the formation of [Co(NH3)5Cl]2+ from [Co(NH3)5(OH2)]3+ ?
To write a balanced equation for the formation of [Co(NH3)5Cl]2+ from [Co(NH3)5(OH2)]3+, you need to consider the changes in the coordination complex.
Here's how you can do it step by step:
Step 1: Write the formula for [Co(NH3)5(OH2)]3+ and [Co(NH3)5Cl]2+ ions.
[Co(NH3)5(OH2)]3+ → [Co(NH3)5Cl]2+
Step 2: Identify the ions that are changing and determine the oxidation states.
In this case, Co is changing its ligand from OH2 (water) to Cl. The oxidation state of Co remains the same since the overall charge is constant.
Step 3: Write down the ligand substitution reaction.
[Co(NH3)5(OH2)]3+ + Cl^- → [Co(NH3)5Cl]2+ + OH^-
Step 4: Balance the charges by adjusting the coefficients.
The overall charge on the left side of the reaction is +1 (+3 from [Co(NH3)5(OH2)]3+ and -2 from Cl^-), while on the right side, it is 0 (+2 from [Co(NH3)5Cl]2+ and -2 from OH^-).
To balance the charges, place a 2 in front of [Co(NH3)5Cl]2+ and OH^-. The balanced equation becomes:
[Co(NH3)5(OH2)]3+ + 2Cl^- → [Co(NH3)5Cl]2+ + 2OH^-
Now you have the balanced equation for the formation of [Co(NH3)5Cl]2+ from [Co(NH3)5(OH2)]3+. Remember, it's important to pay attention to the changes in ligands and oxidation states, as well as balancing charges to write a balanced equation.