I posted this the other day but no one responeded. Yes, I am looking for the steps and a answer because I can not get it.

Question: Area of Painting: A rectangular painting with a width of x centimeters has an area X^2 +50x square centimeters. Find a binomial that represents the length.

X^2 +50x factors and

= x(x + 50)

clearly, x must be a positive number, so clearly x+50 is larger than x

Usually, in talking about length and width, the length is the larger of the two dimensions, isn't it ?

So, what do you think?

To be honest, I could not figure out this problem. I don't know why I am so confused..

Area = width x length

X^2 +50x = x(x+50)

so x must be the width
x+50 must be the length

How do you multiply fractions like 1-5 x 2-5 please help me with my home work please.

To find a binomial that represents the length of the rectangular painting, we need to use the formula for the area of a rectangle.

The formula for the area of a rectangle is given by:

Area = length * width

In this case, the width of the painting is x centimeters, and the area is (x^2 + 50x) square centimeters. We need to rearrange the formula to solve for the length.

So, let's start by substituting the given values into the formula:

(x^2 + 50x) = length * x

Now, we can divide both sides of the equation by x to isolate the length:

(x^2 + 50x) / x = length

Simplifying the right side of the equation, we get:

x + 50 = length

Therefore, the binomial that represents the length of the rectangular painting is (x + 50) centimeters.