Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist eho is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
Math word problem - drwls, Wednesday, March 4, 2009 at 10:46am
The faster cyclist "closes the gap" at a rate of 10 - 6 = 4 miles/hour. The initial lead of the slower cyclist is 3*6 = 18 miles.
Divide 18 miles by 4 miles/hour for the answer in hours
Math word problem - Anonymous, Sunday, March 15, 2009 at 3:11am