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Could someone help me with this question

Write in polar form : sinx - i cosx

I've come up to this point, and it's wrong, can't someone please help?


But the answer is cis(x-pie/2)

  • Maths -


    sinx = cos(pi/2 - x) and cosx = sin(pi/2 - x)
    that is, the sine of any angle equals the cosine of its compliment.

    so sinx - i cosx
    = cos(pi/2 - x) - i sin(pi/2 - x)
    = cis(pi/2 - x)

    this webpage has some good examples with simple diagrams to show your topic

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