Question: Suppose you have 557 ml of 0.0300M HCL and you want to make up a solution of HCL that has a pH of 1.831. What is the maximum volume (in liters) that you can make of this solution?

I know that you can get the concentration of HCL using the pH given, but how do you than take that and get the maximum volume that you can use?

pH gives you (H^+).

M x L = M x L.

I would like to know the answer

Yes would like to know the answer

To find the maximum volume of the HCL solution you can make, you need to consider the concentration and the amount of HCL available. Here's how you can calculate it step-by-step:

1. Calculate the amount of moles of HCL you have:
- Given the concentration of 0.0300 M and the initial volume of 557 mL (0.557 L), you can use the formula:
moles of HCL = concentration of HCL × volume of HCL solution
Therefore, moles of HCL = 0.0300 M × 0.557 L

2. Use the definition of pH to find the concentration of H+ ions:
- The pH is given as 1.831. Remember that pH is a negative logarithmic scale of the concentration of H+ ions.
- Calculate the concentration of H+ ions using the formula:
concentration of H+ = 10^(-pH)

3. Convert the concentration of H+ ions into moles:
- Multiply the concentration of H+ ions by the volume of the HCL solution you want to find, which is in liters:
moles of H+ = concentration of H+ × volume of HCL solution

4. Set up an equation to relate the moles of HCL and H+ ions:
- Since HCL dissociates into H+ and Cl- ions in a 1:1 ratio, the moles of HCL and H+ ions will be the same:
moles of HCL = moles of H+

5. Solve the equation to find the volume of the HCL solution you can make:
- Substitute the calculated values from steps 1, 2, and 3 into the equation:
0.0300 M × 0.557 L = concentration of H+ × volume of HCL solution

- Rearrange the equation to solve for the volume of HCL solution:
volume of HCL solution = (0.0300 M × 0.557 L) / concentration of H+

That's how you can find the maximum volume (in liters) of the HCL solution that will have a pH of 1.831, using the given concentration of HCL.