posted by Anonymous on .
acid: HCI 0.10 M
Base:NaOH O.050 M
3 ml of HCI was used.
Calculate the volume of base required to reach the equivalence point of this titration.
Somewhere in the finding the solution, i have to use the fact that
Moles HCl = moles NaOH.
this is what i have so far:
Volume of base= [(Molarity of NaOH)( Volume of NaOH)]/Molarity of HCI
(0.050 M)( mL) = (0.10 M)(x mL)
when do i use Moles HCl = moles NaOH.
Your work is off.