Graph the linear equation.
I need coordinates, but don't think they match up to my choices. I would appreciate some feed back. ThankS!
4y + 36x = -32
...what were your coordinates?
That is what i need to know, i figured out that 4(-17) + 36 (0)
4(-17) + 36 (0) = -68 + 36 = -32
X = 0
Y = 0
To graph the linear equation 4y + 36x = -32, we first need to rearrange it in the slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.
Let's rearrange the equation step by step:
4y + 36x = -32
First, subtract 36x from both sides:
4y = -36x - 32
Next, divide the entire equation by 4:
y = (-36/4)x - 8
Simplifying further, we have:
y = -9x - 8
Now, we can identify the slope and the y-intercept:
The slope, m, is the coefficient of x, which is -9.
The y-intercept, b, is the constant term, which is -8.
To graph the equation, we start by plotting the y-intercept on the coordinate plane, which is the point (0, -8). Then, using the slope, we can find additional points on the line. The slope of -9 means that for every positive unit moved to the right on the x-axis, we move 9 units downward on the y-axis.
We can now plot a few more points to complete the graph. For example, if we move one unit to the right from the y-intercept, we move 9 units down and get the point (1, -17). If we move two units to the right, we move 18 units down and get the point (2, -26). We can continue this process to find more points.
Once we have plotted enough points, we can connect them to form a straight line.