# Precalculus

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1.A plane takes off at an angle of 6 degrees traveling at the rate of 200 feet/second. If it continues on this flight apth at the same speed, how many minutes will it take to reach a n altitude of 8000 feet?

2. A plane takes off at an angle of 5 degrees. After traveling 1 mile along this flight path, how high (in feet) is the plane above the ground?

• Precalculus - ,

1. The rate of elevation increase is 200* sin 6 = 20.9 ft/s. Divide 8000 feet by that number for the number of SECONDS it takes. Then convert that to minutes. I get about 6 1/3 minutes.

2. 5280 feet* sin 5

• Precalculus - ,

Another question is a guy wire stretches from the top of an antenna tower to a point on level ground 18 feet from the base of the tower. The angle between the wire and the ground is 63 degrees. How high is the tower?

So said the tower was 3503 fet high because i did tan63 * 18; I feel this answer is wrong..if it is can you please give me the right answer and explain why my mehtod was wrong?

• Precalculus - ,

mmmhh, my calculator says 18(tan63) = 35.32

• Precalculus - ,

• Precalculus - ,

tan 63 = height/18
height = 18tan63
= 35.32

yes

• Precalculus - ,

thanx much!

• Precalculus - ,

good job ladies. that's what i like to see. :)

• Precalculus - ,

lolz thanx