Posted by Ms. Suzie on Monday, March 2, 2009 at 12:27pm.
1.A plane takes off at an angle of 6 degrees traveling at the rate of 200 feet/second. If it continues on this flight apth at the same speed, how many minutes will it take to reach a n altitude of 8000 feet?
2. A plane takes off at an angle of 5 degrees. After traveling 1 mile along this flight path, how high (in feet) is the plane above the ground?
- Precalculus - drwls, Monday, March 2, 2009 at 12:35pm
1. The rate of elevation increase is 200* sin 6 = 20.9 ft/s. Divide 8000 feet by that number for the number of SECONDS it takes. Then convert that to minutes. I get about 6 1/3 minutes.
2. 5280 feet* sin 5
- Precalculus - Ms. Suzie, Monday, March 2, 2009 at 12:40pm
Another question is a guy wire stretches from the top of an antenna tower to a point on level ground 18 feet from the base of the tower. The angle between the wire and the ground is 63 degrees. How high is the tower?
So said the tower was 3503 fet high because i did tan63 * 18; I feel this answer is wrong..if it is can you please give me the right answer and explain why my mehtod was wrong?
- Precalculus - Reiny, Monday, March 2, 2009 at 12:57pm
mmmhh, my calculator says 18(tan63) = 35.32
- Precalculus - Ms. Suzie, Monday, March 2, 2009 at 12:58pm
i asking is this answer the right answer though?
- Precalculus - Reiny, Monday, March 2, 2009 at 1:00pm
tan 63 = height/18
height = 18tan63
- Precalculus - Ms. Suzie, Monday, March 2, 2009 at 1:01pm
- Precalculus - Jenna-fer, Monday, March 2, 2009 at 1:03pm
good job ladies. that's what i like to see. :)
- Precalculus - Ms. Suzie, Monday, March 2, 2009 at 1:06pm
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