the quantity of electricity required to reduce 12.3g of nitrobenzene to aniline assuming 50% current efficiency is
1. 115800 C
2. 57900 C
3. 231600 C
4. 28950 C
Change in o.s=6
Now 6 F is req'd to reduce 1 mole
Therefore for 12.3/123=0.1 mole we need
0.1*6=0.6 F
But since current is 50℅ efficient..
Therefore for 0.6 we need 0.6*2=1.2 F
1.2*96500=115800 C
57900
Mole=6×12.3/123=0.6
Charge= 0.6×96500
As 50% efficiency
So, 2×0.6×96500=115800 C
Change in o.s=6e=6f
123g req.6f
But efficiency is half 50%so
123g req 12f so,
12.3g req 12*12.3/123
=1.2f
In coulomb 1.2*96500=115800
mishra
Check my thinking on this.
C6H5NO2 ==> C6H5NH2
molar mass C6H5NO2 = 123
Change of electrons is 6, N going from +5 oxidation state to -1 oxidation state or gain of 6 electrons.
Therefore, 1 Faraday or 96,485 coulombs will reduce 123/6 = 20.5 g C6H5NO2. But since the efficiency is only 50%, it will reduce only half that amount or 20.5/2 = 10.25 g or 10.25/123 = 0.08333 mole.
How many moles do we have? That is 12.3/123 = 0.1; therefore,
# coulombs = 96,485 C x (0.1/0.08333)= ??
Check my work.