Wow, that's a big post
#1 you want 1000(e^.05t) not ^.5t
so 1000(e^.5) = 1051.24 --- one year
1000(e^(.10) = 1105.17
#2. your equation is
number = 500(1.5)^t, where t is in hours
so one day is 24 hours
number - 500(1.5)^24 = 8 417 056
#3 amount = 1mill(1 - .15)^t , where t is in years.
so after 10 years
amount = 1mill(.85)^10
so 19.7% of the glacier is left.
#4 looks like weight = 2(1.1)^t , where t is in seconds.
Can you take it from here?
Yeah, I'll try to finish it off.
I have a problem on number 1 and number 4.
For number 1, I can't get the same answer your getting for some reason
I punch in the same numbers and I keep getting the same answers
A=1000(e^(.5x1)) = 1648.72
A=1000(e^(.5x2)) = 2718.28
A=1000(e^(.5x5)) = 12182.49
I read your directions on that, but I still do not understand.
For number 4.
Where did you get 1.1 from?
Oh for number 4
Did you do 2(1 + .1) to get 1.1? because of the 10%?
On #1, you are not following Reiny's direction to multiply by e^0.05t, rather than e^0.5t
On #4, there is a difference between increasing 10% every 1 second and increasing at a rate of 10% per second, because the rate is continuously increasing, and will be higher at the end of each second.
In the former case, the growth is given by weight = 2*(1.1)^t
After 1 second, the weight is 2.2 lb in this case.
In the latter case,
dW/dt = 0.1W
log W = 0.1 t + log Wo
W = Wo*e^0.1t (where Wo = 2 lb)
W(t=1 s) = 2*e^0.1 = 2.2103 lb
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