Post a New Question

algebra 1

posted by .

how do you factor completely 3(x - 2)^2 - 3(x - 2) - 6

  • algebra 1 -

    That can be recognized as a polynomial in x-2. It factors into
    [3(x-2)+3][(x-2) -2]
    which simplifies to
    = (3x+3)(x-4) = 3(x+1)(x-4)

    Another way to do that would be to multiply out the polynomial 3(x-2)^2 -3(x-2) -6 BEFORE factoring it. The answer should be the same.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question