how do you simplify
1.(8vv-2)(8v+2)
2. (3a-5)(3a+5)
You use the distribution property. For ex in number one you would do 8 times 8 which is 64-2+2=? Then for the second one you would do 3 times 3 which is 9-25=? I think. I did this kind of math a long time ago
Is 8vv supposed to be 8v?
Use the fact that
(a + b)(a - b) = a^2 - b^2
no, it's 8vv.
To simplify expressions like (8vv-2)(8v+2), you can use the distributive property which states that a(b + c) = ab + ac. This means that you need to multiply each term in the first set of parentheses by each term in the second set of parentheses.
Let's simplify each expression step by step:
1. (8vv - 2)(8v + 2):
First, multiply the terms in the parentheses according to the distributive property:
8vv * 8v + 8vv * 2 - 2 * 8v - 2 * 2
Now, simplify each term:
64v^3 + 16vv - 16v - 4
Therefore, the simplified form of (8vv - 2)(8v + 2) is 64v^3 + 16vv - 16v - 4.
2. (3a - 5)(3a + 5):
Using the distributive property, multiply each term in the parentheses:
3a * 3a + 3a * 5 - 5 * 3a - 5 * 5
Now, simplify each term:
9a^2 + 15a - 15a - 25
The like terms "-15a" and "+15a" will cancel each other out, so the expression simplifies to:
9a^2 - 25
Therefore, the simplified form of (3a - 5)(3a + 5) is 9a^2 - 25.