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September 22, 2014

September 22, 2014

Posted by **lt** on Sunday, March 1, 2009 at 6:09pm.

Find standard form a +bi

(4 square root -9) ( -3 square root -5)

x^2 -3x+4 evaluated for x=1+i

- Math -
**lt**, Sunday, March 1, 2009 at 6:20pmFor the second one i got 1+3i is this correct

- Math -
**Damon**, Sunday, March 1, 2009 at 6:23pm4 (-9)^.5 * -3 (-5)^.5

-12 (45)^.5

-12 (3*3*5)^.5

-36 sqrt 5

(1+i)^2 -3(1+i) + 4

=

1 + 2 i - 1 - 3 - 3 i + 4

=

(1 -i)

- Math -
**lt**, Sunday, March 1, 2009 at 6:29pmDoesnt i^2 equal -1

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