Questions LLC
Login
or
Sign Up
Ask a New Question
Questions
Math
how do you factor 16x^2-25y^2?
1 answer
Note that it is the difference of two perfect squares: the squares of 4x and 5y. Whenever that happens, there is a simple way to factor.
Hint: a^2 - b^2 = (a+b)(a-b)
You can
ask a new question
or
answer this question
.
Related Questions
Find the HCF and LCM of:
1 + 4x + 4x^2 - 16x^4.. ,1 + 2x - 8x^3 - 16x^4.., 16x^4 + 4x^2 + 1
1. 16x^2 + 2 + 2x - 15x^2 - 1 + 14x
A. 31x^2 + 16x + 1 B. x^2 - 12x + 1 **** C. x^2 + 16x + 1 D. x^2 + 16x + 2 2. 2x^2 + 8 - 4x +
Which of the following gives an example of a function that is not linear?(1 point)Responsesy=x2−3x+2.25y equals x squared
Standard form for both equation with steps
16x^2-96x+144+25y^2=400 16x^2+192x+576+25y^2=1600
Standard form for both equation with steps
16x^2-96x+144+25y^2=400 16x^2+192x+576+25y^2=1600
(6x-5y)^2=
36x-25y 6x-5y (4x+5y)^2 16x+25y 4x+5y Please check to see if right. If not corrected for me.
Find the points where these conics intercept:
16x^2 - 5y^2 = 64 16x^2 + 25y^2 - 96x = 256
Find the points where these quadratic relations intersect. 16x^2-5y^2=64, 16x^2+25y^2-96x=256
How do I factor these:
2x2 - 16x + 30 4x^2-9 x^2-5x 5x^2-26x+5 25x^2+4 Example: 2x^2 - 16x + 30 = 2 (x^2 - 8 x + 15) 2(x - 5)(x -
solve by substitution.
0.5x+0.25y=36 y+18=16x