A forearm with a mass of 1.2kg supports a put with a mass of 5.44 kg. The forearm is 0.050m long; it's perpendicular to the arm is 0.35m long, the center of gravity is at 0.15m from the elbow. Find the force exerted by rhe biceps and the force on the elbow joint.
What is a "put" ? Do you mean a "shot" such as is used in a shotput event? The mass is about right for a woman's event (12 pounds).
I am confused by the description of the arm's position. Is the forearm horizontal? If so, the elbow supports the weight of the shot and of the forearm. It seems to me the force holding the forearm horizontal while holding the shot is exerted by the triceps, not the biceps
To find the force exerted by the biceps and the force on the elbow joint, we can analyze the equilibrium of the forearm and the put.
Firstly, let's calculate the weight of both the forearm and the put. The weight can be found using the equation:
Weight = mass * acceleration due to gravity (g)
Weight of the forearm = mass of the forearm * g = 1.2 kg * 9.8 m/s^2 = 11.76 N
Weight of the put = mass of the put * g = 5.44 kg * 9.8 m/s^2 = 53.312 N
Now, let's consider the forces acting on the forearm. There are two forces: the force exerted by the biceps and the force at the elbow joint. These forces must balance the weight of the forearm and the put.
Let's denote the force exerted by the biceps as F_biceps and the force at the elbow joint as F_elbow.
In the vertical direction:
F_biceps - Weight of the forearm - Weight of the put = 0
In the horizontal direction:
F_elbow = 0 (since there is no horizontal acceleration)
We can solve both equations simultaneously to find the values of F_biceps and F_elbow.
From the first equation:
F_biceps - 11.76 N - 53.312 N = 0
F_biceps = 11.76 N + 53.312 N = 65.072 N
From the second equation:
F_elbow = 0 N
Therefore, the force exerted by the biceps is 65.072 N, and the force on the elbow joint is 0 N.