Question

(3y^8)^4

_________
(2zy^2)

Answer 1

And your question is? Do you want simplification? If so:

(81y^30)/(2z) should fit the bill. Remember when you have powers inside a bracket taken to another power outside of the bracket ex: (2x^2)^3 The powers multiply together, so (2x^2)^3=(2^3)(x^6).

As for the y^2 on the denominator of your problem: (y^32)/(y^2)=y^30, the powers are subtracted.