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February 28, 2015

February 28, 2015

Posted by **zak** on Thursday, February 26, 2009 at 11:21pm.

I know that I am suppose to use

y= ye^kt , to get the equation and then plug in the info. to get the time, but I'm not sure how to start, please help! Thanks!

- calculus -
**Reiny**, Thursday, February 26, 2009 at 11:55pmy = a e^(kt) where a is the initial amount

so y = 10(e^(kt))

when t = 24100, y = 5 ---> you should have 1/2 of the original 10 g left.

0.5 = e^(24100k)

24100k = ln(0.5)

k = ln(.5)/24100

so y = 10(e^(t)(ln.5/24100))

so you want y to be 1

1 = 10 (e^(t)(ln.5/24100))

0.1 = (e^(t)(ln.5/24100))

(t)(ln.5/24100)) = ln .1

t = 80059

so about 80,000 years !!!!

- calculus -
**zak**, Friday, February 27, 2009 at 3:06amOhhh, I get it!! Thanks so much, you helped me a lot! :)

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