Posted by zak on Thursday, February 26, 2009 at 11:21pm.
y = a e^(kt) where a is the initial amount
so y = 10(e^(kt))
when t = 24100, y = 5 ---> you should have 1/2 of the original 10 g left.
0.5 = e^(24100k)
24100k = ln(0.5)
k = ln(.5)/24100
so y = 10(e^(t)(ln.5/24100))
so you want y to be 1
1 = 10 (e^(t)(ln.5/24100))
0.1 = (e^(t)(ln.5/24100))
(t)(ln.5/24100)) = ln .1
t = 80059
so about 80,000 years !!!!
Ohhh, I get it!! Thanks so much, you helped me a lot! :)
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