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math algebra

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A student walks and jogs to college each day. She averages 5km/h walking and 9km/h jogging. The distance from home to college is 8km and she makes the trip in 1 hour. How far does the student jog.

To set up the equation I got:

5(x)+9(8-x)=8

5x+72-9x=8
-4x=-64
x=16

but this gives me a negative number for the walking.

WHAT IS THE CORRECT WAY TO SET UP AND SOLVE THE EQUATION?

  • math algebra -

    You x is TIME, not distance
    5(x) + 9 (1-x) = 8
    5 x + 9 -9 x = 8
    - 4x = - 1
    x = 1/4 or 15 minutes walking
    3/4 hour jogging
    3/4 * 9 = 27/4 = 6.75 km jogging

  • math algebra -

    OOOH! I see, thanks for the help!

  • math algebra -

    i need help with my homewok please help out and is hard that why i am asking help.

  • math algebra (surer) -

    Post your question separately, not as part of this question. Click on the link at the top labeled "Post a new question"

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