Posted by angela on Thursday, February 26, 2009 at 7:54am.
A student walks and jogs to college each day. She averages 5km/h walking and 9km/h jogging. The distance from home to college is 8km and she makes the trip in 1 hour. How far does the student jog.
To set up the equation I got:
5(x)+9(8x)=8
5x+729x=8
4x=64
x=16
but this gives me a negative number for the walking.
WHAT IS THE CORRECT WAY TO SET UP AND SOLVE THE EQUATION?

math algebra  Damon, Thursday, February 26, 2009 at 8:02am
You x is TIME, not distance
5(x) + 9 (1x) = 8
5 x + 9 9 x = 8
 4x =  1
x = 1/4 or 15 minutes walking
3/4 hour jogging
3/4 * 9 = 27/4 = 6.75 km jogging

math algebra  mark, Thursday, February 26, 2009 at 8:06am
OOOH! I see, thanks for the help!

math algebra  surer, Thursday, February 26, 2009 at 10:26am
i need help with my homewok please help out and is hard that why i am asking help.

math algebra (surer)  drwls, Thursday, February 26, 2009 at 5:57pm
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