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September 19, 2014

Homework Help: math algebra

Posted by angela on Thursday, February 26, 2009 at 7:54am.

A student walks and jogs to college each day. She averages 5km/h walking and 9km/h jogging. The distance from home to college is 8km and she makes the trip in 1 hour. How far does the student jog.

To set up the equation I got:

5(x)+9(8-x)=8

5x+72-9x=8
-4x=-64
x=16

but this gives me a negative number for the walking.

WHAT IS THE CORRECT WAY TO SET UP AND SOLVE THE EQUATION?

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