which of the sets of points are collinear and lie on (2?
im not sure that's just how they are set i have to find the reverse distribution for each set
To determine which sets of points are collinear and lie on the line \(x = 2\), we need to check if the \(x\) coordinates of all the points in the set are equal to 2.
For example, let's consider three sets of points: Set A, Set B, and Set C.
Set A: \((2, 3), (2, 5), (2, -1)\)
Set B: \((2, 4), (3, 4), (2, 2)\)
Set C: \((2, 6), (2, 7), (2, 8)\)
To check if Set A is collinear and lies on the line \(x = 2\), we need to ensure that the \(x\) coordinates of all the points in the set are 2. In this case, \((2, 3), (2, 5),\) and \((2, -1)\) all have \(x = 2\), so Set A is collinear and lies on the line \(x = 2\).
Similarly, we can check the other sets. For Set B, we see that \((2, 4)\) and \((2, 2)\) have \(x = 2\), but \((3, 4)\) does not. Therefore, Set B is not collinear and does not lie on the line \(x = 2\).
Lastly, for Set C, all the points \((2, 6), (2, 7),\) and \((2, 8)\) have \(x = 2\), so Set C is collinear and lies on the line \(x = 2\).
Therefore, the set of points that are collinear and lie on the line \(x = 2\) is Set A: \((2, 3), (2, 5), (2, -1)\).