#8 has no solution, here is why...
1st one times 5
20x + 40y = 25
2nd one times 4
20x + 40y = 52
0 = 27 which is false
if it ever happens that the variables disappear and the remaining statement is false, there is no solution.
If the remaining statement would be true, such as in 0 = 0, there would be an infinite number of solutions.
1st one :
13 = 8a - 8b
2nd one times 2
12 = 8a - 10b
subtract the first equation minus the new second one
1 = 2b
b = 1/2
back in #1
13 = 8a - 4
17 = 8a
a = 17/8
check in original 2nd
LS = 6
RS = 4(17/8) - 5(1/2)
= 17/2 - 5/2
= 12/2 = 6 = LS
#10 is just like #8
see if you finish it yourself
a times a + b times b =11 and a times b =3 what does a and b equals
two kinds of grouping symbols
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