a golf club exerts and average force of 1000N on a 0.045-kg golf ball which is initially at rest. the club is in contact with the ball for 1.8ms. what is the speed of the golfbal it leaves the tee?
a batter applies an average force if 8000N to a baseball for 1.10ms. what is the magnitude of the impulse delivered to the baseball ?
1. Impulse = (force)(time) = change of momentum = m(change of velocity)
Solve that for the final velocity
2. Use the same equation, but in this case you just want the impulse: force x time
To find the speed of the golf ball as it leaves the tee, we can use the principle of impulse-momentum.
Step 1: Find the impulse experienced by the golf ball.
Impulse (J) is calculated using the formula J = F * Δt, where F is the force exerted on the ball and Δt is the time for which the force is applied.
Given: F = 1000 N, Δt = 1.8 ms = 0.0018 s
J = 1000 N * 0.0018 s
J = 1.8 Ns
Step 2: Calculate the change in momentum of the golf ball.
Change in momentum (Δp) is equal to impulse (J).
Δp = J
Δp = 1.8 Ns
Step 3: Find the velocity of the golf ball.
Momentum (p) is calculated using the formula p = m * v, where m is the mass of the ball and v is its velocity.
Given: m = 0.045 kg
Δp = m * Δv
1.8 Ns = 0.045 kg * Δv
Δv = 1.8 Ns / 0.045 kg
Δv = 40 m/s
Hence, the speed of the golf ball as it leaves the tee is 40 m/s.
Now let's find the magnitude of the impulse delivered to the baseball.
Given: F = 8000 N, Δt = 1.10 ms = 0.0011 s
Step 1: Calculate the impulse experienced by the baseball.
J = F * Δt
J = 8000 N * 0.0011 s
J = 8.8 Ns
Hence, the magnitude of the impulse delivered to the baseball is 8.8 Ns.
To find the speed of the golf ball as it leaves the tee, we can use the concept of impulse.
Impulse is defined as the change in momentum of an object and is given by the product of the force applied and the time during which it is applied. It can be calculated using the formula:
Impulse = Force × Time
Now, let's calculate the impulse exerted on the golf ball and use it to find its final velocity.
Given:
Force (F) = 1000 N
Time (Δt) = 1.8 ms = 0.0018 s
Mass (m) = 0.045 kg (not used directly in this calculation)
Using the formula for impulse:
Impulse = F × Δt
I = 1000 N × 0.0018 s
I = 1.8 N•s
Next, we'll use the principle of conservation of momentum to relate the impulse to the change in momentum of the golf ball. The change in momentum (Δp) is given by the product of mass and change in velocity:
Δp = m × Δv
Since the golf ball is initially at rest (0 m/s), the initial momentum (p_initial) is 0. Therefore, the impulse is equal to the final momentum (p_final):
Impulse = Δp
1.8 N•s = m × Δv
Rearranging the equation and solving for Δv:
Δv = 1.8 N•s / m
Substituting the given mass value:
Δv = 1.8 N•s / 0.045 kg
Δv = 40 m/s
Therefore, the speed of the golf ball as it leaves the tee is 40 m/s.
Now let's move on to the second question about the magnitude of the impulse delivered to the baseball.
To find the magnitude of the impulse, we'll use the same formula as before:
Impulse = Force × Time
Given:
Force (F) = 8000 N
Time (Δt) = 1.10 ms = 0.0011 s
Using the formula for impulse:
Impulse = 8000 N × 0.0011 s
Impulse = 8.8 N•s
Therefore, the magnitude of the impulse delivered to the baseball is 8.8 N•s.