Posted by sue on Wednesday, February 25, 2009 at 1:10pm.
solve the system of equation
5x+2y+z=25
5x3yz=23
3x+y+2z=9

math  Anneliese, Wednesday, February 25, 2009 at 2:25pm
Uggh... I am doing the same thing right now, and not fully understanding either, but I'll try to explain.
What I was told is to solve the first equation for x or another variable. In this case, it would be easier to do z because it doesn't have a number next to it. Basically, get all of the other junk on the other side so it is "z = blah blah blah."
Then, do the substitution method. If you don't know how to do this, write a response back and I'll explain more in depth. But basically, in the second and third equations, substitute z for whatever you got on the other side of the equal sign (should be 5x  2y  25).
That makes there only be x and y in the second and third equations. Then, if you know how, do elimination. If you don't know how to do this, either, I can explain more in depth if you respond back.
After that, solve one of the variables in the equation, and then find the other.
You should have an ordered triple instead of the ordered pair. Instead of the usual answer (x,y) it should be (x,y,z), or three answers, one for each variable.
Hopefully I helped! 
math  sue, Wednesday, February 25, 2009 at 2:33pm
now I'm confused even more