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March 3, 2015

March 3, 2015

Posted by **Amy** on Wednesday, February 25, 2009 at 1:39am.

- Physics -
**drwls**, Wednesday, February 25, 2009 at 2:25amThere are several ways to do this. Let's try conservation of energy. The loss of potential coming down (M g H)is equal to the gain in kinetic energy, (1/2) M V^2, PLUS work done against friction while sliding. The length of the slide is H/sin 28 = 7.46m, where H = 3.5 m is the vertical height. The friction force is M g cos28*uk. The friction work done is therefore

W = M g (H/sin 28)* cos28 *uk

= M g uk/tan28

M g H = M g H uk/tan 28 + (1/2)M V^2

Note that the M's cancel. That's good, because they did not tell you what the mass was.

V^2 = 2 g H [1 - uk/tan28]

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