Posted by Sh on Tuesday, February 24, 2009 at 10:45pm.
solve each identity algebraically
1)(1tanx)/(1cotx)=tanx
2)(1+cotx)/(1+tanx)=cotx

math  Reiny, Tuesday, February 24, 2009 at 11:02pm
my usual approach is to start with the "messy" side, and change everything to sines and cosines.
LS
=(1 sinx/cosx)/(1  cosx/sinx)
= (cosxsinx)/cosx * (sinx)/ (sinx  cosx)
= (1)sinx/cosx
= tanx
perform similar steps for the second one, bet you'll get it

math  Sh, Tuesday, February 24, 2009 at 11:07pm
I got (1 sinx/cosx)/(1  cosx/sinx)
but how did (1 sinx/cosx) turn to (cosxsinx)/cosx?

math  Sh, Tuesday, February 24, 2009 at 11:29pm
nevermind, found out :) thanks
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