Posted by **Sh** on Tuesday, February 24, 2009 at 10:45pm.

solve each identity algebraically

1)(1-tanx)/(1-cotx)=-tanx

2)(1+cotx)/(1+tanx)=cotx

- math -
**Reiny**, Tuesday, February 24, 2009 at 11:02pm
my usual approach is to start with the "messy" side, and change everything to sines and cosines.

LS

=(1- sinx/cosx)/(1 - cosx/sinx)

= (cosx-sinx)/cosx * (sinx)/ (sinx - cosx)

= (-1)sinx/cosx

= -tanx

perform similar steps for the second one, bet you'll get it

- math -
**Sh**, Tuesday, February 24, 2009 at 11:07pm
I got (1- sinx/cosx)/(1 - cosx/sinx)

but how did (1- sinx/cosx) turn to (cosx-sinx)/cosx?

- math -
**Sh**, Tuesday, February 24, 2009 at 11:29pm
nevermind, found out :) thanks

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