Posted by Sh on Tuesday, February 24, 2009 at 10:45pm.
solve each identity algebraically
- math - Reiny, Tuesday, February 24, 2009 at 11:02pm
my usual approach is to start with the "messy" side, and change everything to sines and cosines.
=(1- sinx/cosx)/(1 - cosx/sinx)
= (cosx-sinx)/cosx * (sinx)/ (sinx - cosx)
perform similar steps for the second one, bet you'll get it
- math - Sh, Tuesday, February 24, 2009 at 11:07pm
I got (1- sinx/cosx)/(1 - cosx/sinx)
but how did (1- sinx/cosx) turn to (cosx-sinx)/cosx?
- math - Sh, Tuesday, February 24, 2009 at 11:29pm
nevermind, found out :) thanks
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