Posted by **Lena** on Tuesday, February 24, 2009 at 8:11pm.

The question is as followed:

y=-3x^2 + 4x

This is how I solved it:

y=-3x^2 + 4x

y= -3 (x^2 + 4/3x)

y= -3(x^2+4/3x +4/9) + 4/3

y= -3 (x+2/3)^2 + 4/3

The answer sheet said that x = 2/3 but wouldn't it equal -2/3 because there is a -3 before the bracket?

## Answer this Question

## Related Questions

- Caluclus - Find the absolute maximum and absolute minimum of f on the interval...
- Algebra- Maximum and minimum. - I dont understand how to find the maximum and ...
- calculus - there are no examples of this type of problem in my book so if you ...
- Please check my Calculus - 1. Find all points of inflection: f(x)=1/12x^4-2x^2+...
- Calculus (pleas help!!!) - Find the absolute maximum and absolute minimum ...
- Calculus (pleas help!!!) - Find the absolute maximum and absolute minimum values...
- math - I'm having some troubles with these. Thanks in advance. If a>0 find ...
- maths - Given p(x)=x^4+ax^3+bx^2+cx+d,such that x=0 is the only real root of p'(...
- maths - Given p(x)=x^4+ax^3+bx^2+cx+d,such that x=0 is the only real root of p'(...
- Calculus - Use analytical methods to find the exact global maximum and minimum ...

More Related Questions