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Find the minimum/maximum

posted by on .

The question is as followed:

y=-3x^2 + 4x

This is how I solved it:

y=-3x^2 + 4x
y= -3 (x^2 + 4/3x)
y= -3(x^2+4/3x +4/9) + 4/3
y= -3 (x+2/3)^2 + 4/3

The answer sheet said that x = 2/3 but wouldn't it equal -2/3 because there is a -3 before the bracket?

  • Find the minimum/maximum - ,

    y=-3x^2 + 4x
    y= -3 (x^2 + 4/3x)You erred here, it should be
    y=-3x^2 + 4x
    y= -3 (x^2 - 4/3x )

  • Find the minimum/maximum - ,

    oh ok
    thanks so much :)

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