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September 15, 2014

September 15, 2014

Posted by **RuggedChild** on Tuesday, February 24, 2009 at 2:42pm.

- Calculus II -
**drwls**, Tuesday, February 24, 2009 at 3:56pmThe work required is proportional to the height, measured from the bottom.

This integral is S (pi*R(H)^2)*(density)*g H dH. S denotes the integral sign

The cone radius as a function of height is R(H) = H/2

Integrate from H = 0 to h = 20 ft

In these British units, (density* g = 62.4 lb/ft^3. The answer will be in ft-lb

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