Deduce the electric field strenght at a point midway between charges of 7.210^-6 C and -3.410^-6 C that are 2.0m apart from air.

Question

Deduce the electric field strenght at a point midway between charges of 7.210^-6 C and -3.410^-6 C that are 2.0m apart from air.

Thank you!

Answer 1

Calculate E from each, then add. Now in between, both will point the same direction, so add the absolute values.

E=kq/distance^2

Answer 2

For the 7.210-6C I get 16200 and for -3.410^-6 I get -7650. Because one value is positive and the other is negative, does this mean I need to add these values together (including the minus) or take away?

Answer 3

Thank you bobpursley!

Sorry about the question before, I didn't know what an absolute value was- but I checked it on wikipedia

Answer 4

To deduce the electric field strength at a point midway between the two charges, you can use Coulomb's law. Coulomb's law states that the electric field strength due to a point charge is directly proportional to the magnitude of the charge and inversely proportional to the square of the distance from the charge.

The formula for Coulomb's law is:

E = k * (Q / r^2)

Where:
E is the electric field strength
k is the electrostatic constant (9 * 10^9 Nm^2/C^2)
Q is the magnitude of the charge
r is the distance from the charge

In this case, we have two charges with magnitudes of 7.2 * 10^-6 C and -3.4 * 10^-6 C, respectively. These charges are 2.0m apart, and we want to find the electric field strength at the midpoint between them.

First, we need to find the distance from the midpoint to each of the charges. Since the charges are 2.0m apart, the distance from the midpoint to each charge would be 1.0m.

Now, let's calculate the electric field strength at the midpoint for each charge:

For the positive charge (7.2 * 10^-6 C):
E1 = k * (Q1 / r^2) = (9 * 10^9 Nm^2/C^2) * (7.2 * 10^-6 C / (1.0m)^2) = 6.48 N/C

For the negative charge (-3.4 * 10^-6 C):
E2 = k * (Q2 / r^2) = (9 * 10^9 Nm^2/C^2) * (-3.4 * 10^-6 C / (1.0m)^2) = -3.06 N/C

The electric field strength at the midpoint would be the vector sum of these two values:

E_total = E1 + E2 = 6.48 N/C - 3.06 N/C = 3.42 N/C

Therefore, the electric field strength at the point midway between the two charges is 3.42 N/C.

Answer 5

Deduce the electric field strenght at a point midway between charges of 7.210^-6 C and -3.410^-6 C that are 2.0m apart from air.

Calculate E from each, then add. Now in between, both will point the same direction, so add the absolute values.

For the 7.210-6C I get 16200 and for -3.410^-6 I get -7650. Because one value is positive and the other is negative, does this mean I need to add these values together (including the minus) or take away?

Thank you bobpursley!

8550

Reread what I said. Which way does each point? Goodness.

Deduce the electric field strenght at a point midway between charges of 7.2*10^-6 C and -3.4*10^-6 C that are 2.0m apart from air.

Calculate E from each, then add. Now in between, both will point the same direction, so add the absolute values.

For the 7.2*10-6C I get 16200 and for -3.4*10^-6 I get -7650. Because one value is positive and the other is negative, does this mean I need to add these values together (including the minus) or take away?

Thank you bobpursley!

8550

Reread what I said. Which way does each point? Goodness.

Deduce the electric field strenght at a point midway between charges of 7.210^-6 C and -3.410^-6 C that are 2.0m apart from air.

For the 7.210-6C I get 16200 and for -3.410^-6 I get -7650. Because one value is positive and the other is negative, does this mean I need to add these values together (including the minus) or take away?