Posted by hriday on .
A current of 0.965 A is passed through 500 ml of 0.2 M solution of ZnSO4 for 10 min. The molarity of Zn 2+ after deposition of Zn is
amperes x seconds = coulombs.
coulombs/96,485 = Faradays
1 Faraday will deposit 1 equivalent weight (1/2 mole) Zn.
Subtract moles Zn from initial Zn concn and change to molarity.