Algebra 1 8th Grade
posted by Joy on .
How do you solve these types of problems?
1) 3  n = 32
3m  8n  6 = 0
2) 2p  q = 8
1/3p + 1/4q = 3

1. substitute 29 for n in the second equation, and solve for q.
(n=29 comes from the first equation)
2. Multiply the second equation by 4 and add them.
2p  q = 8
4/3p + q = 12
10/3 p = 20
p = 6
q = 2p  8 = 4