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April 16, 2014

Homework Help: Chemistry- please check my work

Posted by Eliz on Monday, February 23, 2009 at 9:19pm.

Compute the vapor pressure of water above a solution formed by dissolving 25.00 grams of magnesium sulfate, MgSO4 (MM=120.3) in 95.00 grams of water at 338K. The vapor pressure of pure water at 338K is 188.0 torr.


I took 95.00g H20 divided by 18.0g. which gave me moles for top. I than took those moles and added them to 25.0 divided by 120.3. I than took 5.277 mol H20 divided by 5.4856total moles time 188.0 torr. which i than got 180.88 vapor pressure of water.

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