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If you are given .060m. sugar (glucose-C6H12O6), .030m. AlCl3 and .025m. NaOH.

How do you figur out lowest boiling point and lowest vapor pressure of the given solutions?

  • chemistry - ,

    Lowest boiling point.
    delta T = i*Kb*m
    Since Kb is a constant, you only need to do i*molality.
    i = # dissolved particles. m is molality.
    delta T will be the lowest for the smallest product of i*m

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