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Chemistry

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The element copper, found in nature with an average atomic mass of 63.54u, consists of two isotopes, copper-63 of atomic mass 62.93u and copper-65 of atomic mass 64.93u. Calculate the abundance of each isotope.

I can't come up with an equation to solve it; can someone please help with this?

  • Chemistry - ,

    62.93*(x) + 64.93*(1-x) = 63.54
    where x is decimal equivalent for that isotope and 1-x for the other isotope.

  • Chemistry - ,

    Let the fraction of Copper-65 = x.
    Then Copper-63 would be (1-x)
    We set up an equation for the "weighted average" of copper based on the individual isotopes of copper:
    62.93(1-x) + 64.93x = 63.54
    Solve for x to get the % of Cu-63
    Use (1-x) to get the % of Cu-65

  • Chemistry - ,

    oh ok, I solved it, thank you very much! :]

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