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November 22, 2014

Homework Help: Trig check my work please?

Posted by Carry on Monday, February 23, 2009 at 8:42pm.

8 sin²(3x) cos²(3x) = 2 [2 sin(3x) cos(3x)]²
= 2 [sin(6x)]²
= 2[1 - cos(12x)]/2
= 1 - cos(12x)

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