Sunday

October 26, 2014

October 26, 2014

Posted by **nay** on Monday, February 23, 2009 at 8:41pm.

- physics -
**drwls**, Monday, February 23, 2009 at 9:01pmFirst find out how far it travels while decelerating. Call that distance X. The divide X by 2 pi R to get the number of tire rotations.

The average speed while decelerating is 15.0 m/s. The time required to decelerate to zero speed is (30.0 m/s)/2 m/s^2 = 15 s

X = (average speed) * t = 225 m

Finally, divide that by 2 pi R.

- physics -
**bob**, Tuesday, January 10, 2012 at 7:47am119.37

**Answer this Question**

**Related Questions**

physics - A car initially traveling at 31.0 m/s undergoes a constant negative ...

Physics - A car initially traveling at 33.4 m/s undergoes a constant negative ...

Physics - A car initially traveling at 33.4 m/s undergoes a constant negative ...

physic - Hi!Need help please. Question:A car initially traveling at 24.0 m/s ...

calc - a) A car is traveling at 50 mi/h when the brakes are fully applied, ...

physics - A car initially traveling at 26 m/s hits the brakes, generating a ...

physics - The coefficient of sliding friction between rubber tires and wet ...

Physics - The brakes are applied to a car traveling on a dry, level highway. A ...

physics - The brakes are applied to a car traveling on a dry, level highway. A ...

Physics - A car is traveling at a constant negative velocity of 12.0 m/s. The ...