Friday

December 19, 2014

December 19, 2014

Posted by **Jeff** on Monday, February 23, 2009 at 7:42pm.

- math -
**drwls**, Monday, February 23, 2009 at 8:56pmWhen x = 1/e, u = 0 and y = u + 2e^u = 2

dy/dx = (dy/du)*(du/dx) = (1 + 2e^u)(1/x)

= 3*e = 3e

**Answer this Question**

**Related Questions**

L'Hopital's rule - Find lim x->1+ of [(1/(x-1))-(1/lnx)]. Here is my work...

Calculus 1 - Find the derivative of y with respect to x. y=(x^6/6)(lnx)-(x^6/36...

Calculus - Find the derivatives, dy/dx for the following functions. a. x^2y^4 = ...

Math - Find the coordinates of the turning point and determine wether it is ...

calculus - sorry to ask a second question so soon, but i'm just not getting this...

calculus - (a) find the intervals on which f is incrs or decrs. (b) find the ...

calc - f(x)=3x^ln(x), find f '(9). i can't find the answer :( I got 3x^lnx(((ln(...

College Calc - Problem: y=sqrtx ^1/x. Find DY/DX. ln(f(x))=lnx^1/2x or lnx to ...

calc - integral of 1 to e^4 dx/x(1+lnx) 1+lnx = a => dx/x = da dx/ x(1+lnx...

math - how would you solve for y in this problem: ln(y-1)-ln2 = x +lnx ln(y-1)-...