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September 20, 2014

September 20, 2014

Posted by **Jeff** on Monday, February 23, 2009 at 7:42pm.

- math -
**drwls**, Monday, February 23, 2009 at 8:56pmWhen x = 1/e, u = 0 and y = u + 2e^u = 2

dy/dx = (dy/du)*(du/dx) = (1 + 2e^u)(1/x)

= 3*e = 3e

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