posted by Aimee on .
Compute the vapor pressure of water above a solution formed by dissolving 25.00 grams of magnesium sulfate, MgSO4 (MM=120.3) in 95.00 grams of water at 338K. The vapor pressure of pure water at 338K is 188.0 torr.
P(solvent) = X(solvent)* P(normal v.p. solvent).