Thursday
December 18, 2014

Homework Help: chemistry

Posted by Aimee on Monday, February 23, 2009 at 7:24pm.

A aqueous solution of acetic acid with a density of 1.25 g/ml is 30.0% by mass HC2h3O2 (MM=60.0) Compute the molarity of this solution.

I figured out that if you divide 30.0 by the molar mass 60.0g which gives you .5 mol. I cannot seem to figure out what i change 1.25 g/ml into for the molarity equation.

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