Posted by joanna on Monday, February 23, 2009 at 7:05pm.
Break it up into 3 cases
1. Joe at the door, then 10 others at the door, C(10,4) on the floor, C(6,6) as floaters
= 10x210x1 = 2100
2. Joe on the floor, leaving C(10,3) for the remainder on floor, C(8,2) for the door and C(6,6) as floaters
= 120x28x1 = 3360
3. Joe as floater leaving C(10,5) for the remaining floaters, C(6,4) for the floor, and C(2,2) for the door
= 252x15x1 = 3780
total = 2100+3360+3780 = 9240
thanks!!!
THANK YOU!
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