Posted by John on Monday, February 23, 2009 at 5:52pm.
∫ [(e^x^2-2x)/(e^x^2)] dx
= ∫ [1 - 2x/((e^x^2))] dx
= ∫ [1 - 2x(e^(-x^2))] dx
= x - e^(-x^2) + c
check by differentiating
John, how did you get that integral symbol?
Hey, yeah, cool !
I can do a long one
⌠
⌡
but it takes two lines
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