Posted by **John** on Monday, February 23, 2009 at 5:52pm.

How do you find the anti derivative of: [(e^x^2-2x)/(e^x^2)] ?

∫ [(e^x^2-2x)/(e^x^2)]

((The e^x^2 is: e raised to x squared))

if you could explain and show the steps too, thank you

- math -
**Reiny**, Monday, February 23, 2009 at 6:04pm
∫ [(e^x^2-2x)/(e^x^2)] dx

= ∫ [1 - 2x/((e^x^2))] dx

= ∫ [1 - 2x(e^(-x^2))] dx

= x - e^(-x^2) + c

check by differentiating

- JOHN math -
**Reiny**, Monday, February 23, 2009 at 6:07pm
John, how did you get that integral symbol?

- math -
**Damon**, Monday, February 23, 2009 at 6:11pm
Hey, yeah, cool !

- math -
**Reiny**, Monday, February 23, 2009 at 6:15pm
I can do a long one

⌠

⌡

but it takes two lines

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