trig help again i cant get any of these
posted by hayden on .
sin^4cos^2x=(1/16)(1cos 2x)(1cos4x)
work one 1 side only!

pick x=50ยบ
LS = .202..
RS = .379..
Your equation is NOT an identity
I assumed your LS = sin^x4cos^2x
you had sin^2[cos^2x], but I doubt that is what you meant.
(that would be even worse)