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March 28, 2017

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The perimiter of a lot is 190 meters. The width is one-fourth of the length. Find the dimensions.

Here's my system of equations:

2w + 2L = 190
1/4L = w

What would I do from here? I prefer the elimination method. Would I multiply the second equation by 4? When I did so, it kind of messed up the equation.

Thanks! :)

  • Algebra - ,

    I would use substitution, but if you insist on using elimination, multiplying the second equation by 4 gives you
    L = 4W or 4W - L = 0
    now double that:
    8W - 2L = 0 , now the first:
    2W + 2L = 190, now add them
    .
    .
    .

    I'm sure you can finish it.

  • Thank you! - ,

    Did you get w = 19 and L = 76?

    Thanks! :)

  • Algebra - ,

    yes, correct!

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