Posted by **Willow** on Monday, February 23, 2009 at 3:54pm.

The perimiter of a lot is 190 meters. The width is one-fourth of the length. Find the dimensions.

Here's my system of equations:

2w + 2L = 190

1/4L = w

What would I do from here? I prefer the elimination method. Would I multiply the second equation by 4? When I did so, it kind of messed up the equation.

Thanks! :)

- Algebra -
**Reiny**, Monday, February 23, 2009 at 4:06pm
I would use substitution, but if you insist on using elimination, multiplying the second equation by 4 gives you

L = 4W or 4W - L = 0

now double that:

8W - 2L = 0 , now the first:

2W + 2L = 190, now add them

.

.

.

I'm sure you can finish it.

- Thank you! -
**Willow**, Monday, February 23, 2009 at 4:09pm
Did you get w = 19 and L = 76?

Thanks! :)

- Algebra -
**Reiny**, Monday, February 23, 2009 at 4:32pm
yes, correct!

## Answer This Question

## Related Questions

- Algebra - The perimeter of a rectangular lot is 190 ft. The width of the lot is ...
- Math - A rectangle is 40 meters longer than its width if its length were ...
- algebra - the primeter of a rectangle is 24ft. the length is 2 ft longer than ...
- Algebra - Please help me to solve this Radical Expressions and equations word ...
- algebra - the primeter of a rectangle is 24ft. the length is 2 ft longer than ...
- Math - Here is the question: Construct a factor tree of 190. My answer is: 190...
- algebra - The length of a rectangular garden is 5 ft less than 3 times its width...
- algebra , help - Can someone help me set up the equations thanks. Directions: ...
- algebra - the primeter of a rectangle is 24ft. the length is 2 ft longer than ...
- MAT 116 - The perimeter of a rectangle is 28 ft. The length is 10 ft longer than...

More Related Questions