Thursday
October 23, 2014

Homework Help: Algebra

Posted by Willow on Monday, February 23, 2009 at 3:54pm.

The perimiter of a lot is 190 meters. The width is one-fourth of the length. Find the dimensions.

Here's my system of equations:

2w + 2L = 190
1/4L = w

What would I do from here? I prefer the elimination method. Would I multiply the second equation by 4? When I did so, it kind of messed up the equation.

Thanks! :)

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Algebra - The perimeter of a rectangular lot is 190 ft. The width of the lot is ...
algebra - the primeter of a rectangle is 24ft. the length is 2 ft longer than ...
algebra - the primeter of a rectangle is 24ft. the length is 2 ft longer than ...
algebra - the primeter of a rectangle is 24ft. the length is 2 ft longer than ...
MAT 116 - The perimeter of a rectangle is 28 ft. The length is 10 ft longer than...
Math - The perimeter of a rectangle is 42ft. The length is 7ft. longer than the ...
math - A rectangular lot is surrounded by a rock wall 46 meters in length. What ...
Algebra - The perimeter of a rectangle is 90 meters. The length is 9 meters more...
algebra - The length of a rectangular garden is 5 ft less than 3 times its width...
algebra , help - Can someone help me set up the equations thanks. Directions: ...

Search
Members