Tuesday
May 21, 2013

Homework Help: Algebra

Posted by Willow on Monday, February 23, 2009 at 3:54pm.

The perimiter of a lot is 190 meters. The width is one-fourth of the length. Find the dimensions.

Here's my system of equations:

2w + 2L = 190
1/4L = w

What would I do from here? I prefer the elimination method. Would I multiply the second equation by 4? When I did so, it kind of messed up the equation.

Thanks! :)

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

algebra - the primeter of a rectangle is 24ft. the length is 2 ft longer than ...
algebra - the primeter of a rectangle is 24ft. the length is 2 ft longer than ...
math ,correction - Directions: Solve each of the following problems. Be sure to ...
Algebra - The perimeter of a rectangular lot is 190 ft. The width of the lot is ...
Algebra - The perimeter of a rectangle is 90 meters. The length is 9 meters more...
algebra - the primeter of a rectangle is 24ft. the length is 2 ft longer than ...
math - A rectangular lot is surrounded by a rock wall 46 meters in length. What ...
MAT 116 - The perimeter of a rectangle is 28 ft. The length is 10 ft longer than...
Math - The perimeter of a rectangular deck is 175 feet. The length of the deck, ...
algebra - Find the length and width of a rectangular lot with a perimeter of 70 ...

For Further Reading

Search
Members
Community